Sin^2(3x)+cos^2(3x)=1

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Solution for Sin^2(3x)+cos^2(3x)=1 equation: 


Simplifying
Sin2(3x) + cos2(3x) = 1

Remove parenthesis around (3x)
in2S * 3x + cos2(3x) = 1

Reorder the terms for easier multiplication:
3in2S * x + cos2(3x) = 1

Multiply in2S * x
3in2xS + cos2(3x) = 1

Remove parenthesis around (3x)
3in2xS + cos2 * 3x = 1

Reorder the terms for easier multiplication:
3in2xS + 3cos2 * x = 1

Multiply cos2 * x
3in2xS + 3cos2x = 1

Reorder the terms:
3cos2x + 3in2xS = 1

Solving
3cos2x + 3in2xS = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3in2xS' to each side of the equation.
3cos2x + 3in2xS + -3in2xS = 1 + -3in2xS

Combine like terms: 3in2xS + -3in2xS = 0
3cos2x + 0 = 1 + -3in2xS
3cos2x = 1 + -3in2xS

Divide each side by '3os2x'.
c = 0.3333333333o-1s-2x-1 + -1in2o-1s-2S

Simplifying
c = 0.3333333333o-1s-2x-1 + -1in2o-1s-2S

Reorder the terms:
c = -1in2o-1s-2S + 0.3333333333o-1s-2x-1

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